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\title[Asymptotic modeling of thin plastic oscillating layer]
{Asymptotic modeling of thin plastic oscillating layer}%\thanks{LaRI Department ***}}
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\author[A. Ait Moussa ~and ~M. Verid ABDELKADER]{A. Ait Moussa ~and ~M. Verid ABDELKADER}
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\address{Ait Moussa Abdlaziz\\Department of Mathematics. \\
University of Mohammed 1st, \\60000 Oujda, Morroco\\
\\
ABDELKADER Mohamed Verid\\Department of Mathematics. \\
University of Mohammed 1st, \\60000 Oujda, Morroco\\
\email: ab.verid@gmail.com}

\maketitle

\begin{abstract}
In this paper we study the asymptotic behavior of solutions to a elasticity problem, of a containing structure a plastic thin oscillating layer of thickness and rigidity depending of small parameters $\varepsilon$. We use the epi-convergence method to find the limit problems with interface conditions.
\end{abstract}
%%put here Key words

\keywords Limit behavior, plasticity problem, thin oscillating layer, epi-convergence method, subadditive theorem.

\tableofcontents

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\section{Introduction}\label{sec1}
The inclusion of a very thin layer of very rigid material into a given elastic body has been widely considered, and in the classic literature. For more details, we can refer to \cite{Eljaroudi}, \cite{VB}, \cite{Suquet} and \cite{Ait}. In general, the computation of solution using numerical methods is very difficult. In one hind, this is because
the thickness of the adhesive requires a fine mesh, which in turn
implies an increase of the degrees of flexible than the adherents,
and this produces numerical instabilities in the stiffness matrix.
To overcame this difficulties, thanks to Goland and Reissner \cite{Goland}
find a limit problem in which the adhesive  is treated on this
theoretical approach, see for example A. Ait Moussa and J. Messaho
\cite{AitJ}, Acerbi, Buttazzo and Perceivable \cite{AcerbiBP}, Licht
and Michail \cite{LichtM} and A. Ait Moussa and L. Zla\"{\i}ji \cite{AitL}.

In this present work, we consider a structure containing a plastic thin oscillating layer of thickness, rigidity, and
periodicity parameter depending on $\varepsilon$, where $\varepsilon$ being a parameter
intended to tend towards 0. In a such structure, we have treated the
scalar case for a thermal conductivity problem in \cite{AitV}.
The aim of this work is to study the limit behavior of an elasticity
problem with a convex energy functional posed in a such structure.

This paper is organized in the following way. In section 2, we
express the problem to study, and we give some notation and we
define functional spaces for this study in the section 3. In the
section 4, we study the problem (4.1). The section 5 is reserved to
the determination of the limits problems and our main result.
%\section{Statement of the problem }\label{sec2}
\section{Statement of the problem}\label{sec2}
We consider a structure, occupying a bonded domain
$\Omega\in\mathbb{R}^3$ with Lipschitzian boundary
 $\partial\Omega$. It is constituted of two elastic bodies joined
 together by an incompressible rigid thin layer with oscillating
 boundary, the latter obeys to nonlinear elastic low of power type.
 More precisely, the stress field is related to the displacement's
 field by
 \begin{equation*}
    \sigma^\varepsilon= \frac{1}{\varepsilon}~|e(u^\varepsilon)|^{-1}~e(u^\varepsilon),~~\varepsilon>0.
 \end{equation*}
 The structure occupies the regular domain
 $\Omega=B_\varepsilon\cup\Omega_\varepsilon$, where $B_\varepsilon$ is given
 by  $B_\varepsilon = \{x=(x',x_3) ~/~ |x_3|<\frac{\varepsilon}{2}\}$,
 and $\Omega_\varepsilon=\Omega\setminus B_\varepsilon$ represent the regions occupied by
the thin plate and the two elastic bodies, see you Figure 1, $\varepsilon$ being a
positive parameter intended to approach 0, and $\Sigma=\{x=(x',x_3)
~/~ |x_3|=0\}.$ The structure is subjected to a density of forces
of volume $f$, $f:\Omega\rightarrow\mathbb{R}^3$, and it is fixed on
the boundary $\partial\Omega.$ Equations which relate the stress
field $\sigma^\varepsilon$, $\sigma^\varepsilon:\Omega\rightarrow\mathbb{R}_S^9$, and the field
of displacement $u^\varepsilon$,
$u^\varepsilon:\Omega\rightarrow\mathbb{R}^3$ are
$$\left\{\begin{array}{cccc}
  div(\sigma^\varepsilon)+ f = 0 & \text{in} & \Omega \\~~\\
  \sigma_{ij}^\varepsilon= a_{ijkh}e_{kh}(u^\varepsilon) & \text{in} & \Omega_\varepsilon \\~~\\
  \sigma^\varepsilon=\frac{1}{\varepsilon}{|e(u^\varepsilon)|}^{-1}e(u^\varepsilon) & \text{in} & B_\varepsilon \\~~\\
  u^\varepsilon=0 & \text{on} & \partial\Omega
\end{array} ~~ ~~ ~~~ ~~ ~~ ~~ ~~~ ~~ ~~(\mathbb{P}_\epsilon)\right.$$~~
Where $a_{ijkh}$ are the elasticity coefficients, and $\mathbb{R}^9_S$
  the vector space of the square symmetrical matrices of order
three, $e_{ij}(u)$ are the components of the linearized tensor of
deformation $e(u)$.
\begin{figure}
\begin{center}
% Requires \usepackage{graphicx}\
\includegraphics[width=5in,height=3in]{domain1.jpg}
\caption{Domain}\label{fig1}
\end{center}
\end{figure}
$\varphi_\varepsilon$ being a bounded real function and ${]0,\varepsilon[}^2$-periodic.
In the sequel, we assume that the elasticity
coefficients $a_{ijkh}$ satisfy to the following hypotheses :
\begin{eqnarray}\label{sec2}
% \nonumber to remove numbering (before each equation)
 a_{ijkh}\in L^\infty(\Omega) \\
  a_{ijkh}~=~a_{jikh}~=~a_{khij} \\
  a_{ijkh}\tau_{ij}\tau_{kh}\geq C\tau_{ij}\tau_{ij},~\forall\tau\in\mathbb{R}^9_S
\end{eqnarray}


\section{Notation and Function Setting}\label{sec3}
\subsection{Notations}
We begin by introducing some notation which is used throughout the
paper~ $x=(x',x_3)$, where $x'=(x_1,x_2)$,
$\tau\otimes\zeta=(\tau_i\zeta_i)_{1\leq i,j\leq 3}$ and
\begin{equation*}
    \tau\otimes_s\zeta=\frac{\tau\otimes\zeta+\zeta\otimes\tau}{2},~\forall\tau,\zeta\in\mathbb{R}^3;~e^*(.)=(\nabla'+\nabla^{'t})(.);\text{ or}~\nabla'=(\frac{\partial}{\partial x_1},\frac{\partial}{\partial x_2}).
\end{equation*}
We set $Y=]0,1[\times]0,1[$, $\varphi:\mathbb{R}^2\rightarrow [a_1,a_2]$, such as $a_2\geq a_1>0$, and $\varphi$ is $Y$-periodic, $\varphi_\varepsilon(x')=\varphi(\frac{x'}{\varepsilon})$, and
\begin{equation*}
    m(\varphi)=\frac{1}{\int_Ydx'}\int_Y\varphi(x')dx'.
\end{equation*}
In the following $C$ will denote any constant with respect to
$\varepsilon$, $[v]$ is the jump of displacement field $v$ through
$\Sigma,$ and $\nu$, $H_2$ respectively the Lebesgue  Hausdorff
measures. Also, we use the convention $0.(+\infty).$


\subsection{Functions }
First, we introduce the following space :
\begin{equation*}
    V^\varepsilon=\{u\in L^1(\Omega) / e(u)\in L^2(\Omega_\varepsilon,\mathbb{R}_s^9),~~u\in LD_0(B_\varepsilon,\mathbb{R}_s^3),~ {[u]}^\varepsilon=0~\text{in }\Sigma^{\pm}_\varepsilon,\text{ and} ~~u=0 \text{ on }\partial\Omega~ \}
\end{equation*}
where ${[u]}^\varepsilon$ is the jump of $u$ on $\Sigma^{\pm}_\varepsilon$ defined by
\begin{equation*}
    {[u]}^\varepsilon=\pm u_{|_{\Omega_\varepsilon^{\pm}}}\mp u_{|_{B_\varepsilon^{\pm}}},
\end{equation*}
and
\begin{equation*}
  LD_0\{u\in L^1(\Omega,\mathbb{R}^3) / e(u)\in L^1(\Omega,\mathbb{R}_s^9), ~\text{and}~ u=0~ \text{on}~ \partial\Omega\}
\end{equation*}
we easily show that $V^\varepsilon$ is a Banach space with respect
to the norm
\begin{equation*}
u\rightarrow\|e(u)\|_{L^2(\Omega_\varepsilon,\mathbb{R}_s^9)}+\|e(u)\|_{L^1(B_\varepsilon,\mathbb{R}_s^9)}.
\end{equation*}
Our goal in this work is to study the problem $(P_\varepsilon)$, and its limit behavior when $\varepsilon$ tends to zero.


\section{Study of Problem}\label{sec4}
The problem $\mathbb{P}_\varepsilon$ is equivalent of the minimization
problem
\begin{equation}\label{4.1}
    inf_{v\in
V^\varepsilon}\{\frac{1}{2}\int_{\Omega_\varepsilon}a_{ijhk}e_{ij}(v)e_{hk}(v)dx
+ \frac{1}{\varepsilon}\int_{B_\varepsilon}|e(v)| - \int_\Omega fvdx\}
\end{equation}
To study problem $\mathbb{P}_\varepsilon$, we will study the
minimization problem (4.1). The existence and uniqueness of
solutions to (4.1) is given in the following proposition.
\begin{prop} %\label{prop4.1}
Under the hypotheses $(2.1)$, $(2.2)$, $(2.3)$ and for $f\in
L^\infty$, problem $(4.1)$ admits an unique solution.
\end{prop}
\begin{pf}%\label{prop4.1}
From $(2.1)$ and $(2.3)$, we show easily that the energy functional
in $(4.1)$ is weakly lower semicontinuous, strictly convex and
coercive over $V^\varepsilon$, Since $V^\varepsilon$ is not
reflexive, so we may not apply directly result given in Dacorogna
\cite{DA}, but we can follow our proof by using the compact imbedding of Sobolev for
the  $LD_0(\Omega)$ space in the
reflexivity space $L^q(\Omega)$, or $q\in]1,\frac{3}{2}]$ for more
information see Temam (\cite{Temam} p.117).\\ On the other hand, let
$u_n$ be a minimizing sequence for $(4.1)$, to simplify the writing
let
\begin{equation*}
 F^\varepsilon(v)=\frac{1}{2}\int_{\Omega_\varepsilon}a_{ijhk}e_{ij}(v)e_{hk}(v)dx
+ \frac{1}{\varepsilon}\int_{B_\varepsilon}|e(v)| - \int_\Omega fvdx
\end{equation*}
 so, we have
$F^\varepsilon(u_n)\rightarrow\inf_{v\in V^\varepsilon}F(v)$. Using
the coercivity of $F^\varepsilon$, we may then deduce that there
exists a constant $C>0$, independent of $n$, such that
\begin{equation*}\|u_n\|_{V^\varepsilon}\leq C,\end{equation*}
then $u_n$ bounded in $L^q$, therefore a subsequence of $u_n$, still
denoted by $u_n$, there exists $u_0\in V^\varepsilon$ such that
$u_n\rightharpoonup u_0$ in $V^\varepsilon$. The weak lower
semi-continuity and the strict convexity of $F^\varepsilon$ imply
then the result.
\end{pf}

\begin{lem}%\label{prop4.1}
Assuming that for any sequence ${(u^\varepsilon)}_\varepsilon\subset
V^\varepsilon$, there exists a constant $C>0$ such that
$F^\varepsilon(u^\varepsilon)\leq C$, under $(2.1)$, $(2.3)$ and for
$f\in L^\infty(\Omega,\ree^3)$, ${(u^\varepsilon)}_{\varepsilon>0}$
satisfies
 \begin{equation}%\label{sec4}
    \|e(u^\varepsilon)\|^2_{L^2(\Omega_\varepsilon,\ree^9_s)}\leq C
\end{equation}
\begin{equation}
   \frac{1}{\varepsilon} \int_{B_\varepsilon}|e(u^\varepsilon)|\leq C.
\end{equation}
\end{lem}
moreover $u^\varepsilon$ is bounded in $W^{1,1}_0(\Omega,\ree^3).$
\begin{pf}
Science $F^\varepsilon(u^\varepsilon)\leq C$, we have
\begin{equation*}
    \frac{1}{2}\int_{\Omega_\varepsilon}a_{ijhk}e_{ij}(u^\varepsilon)e_{hk}(u^\varepsilon)dx
+ \frac{1}{\varepsilon}\int_{B_\varepsilon}|e(u^\varepsilon)|- \int_\Omega
fu^\varepsilon dx \leq C
\end{equation*}
according to (2.3), we have
\begin{equation}%\lable{sec4}
 \|e(u^\varepsilon)\|^2_{_{L^2{(\Omega_\varepsilon,\mathbb{R}_s^9)}}}
+ \frac{1}{\varepsilon}\int_{B_\varepsilon}|e(u^\varepsilon)| \leq C+C\int_\Omega
fu^\varepsilon dx.
\end{equation}
 Then, taking advantage of the fact that
$u^\varepsilon$ vanishes on $\partial\Omega$ :
\begin{equation*}
\int_\Omega fu^\varepsilon dx= \int_{\Omega_\varepsilon} fu^\varepsilon dx + \int_{B_\varepsilon} fu^\varepsilon dx.
\end{equation*}
Where
\begin{equation}
 \int_{\Omega_\varepsilon} fu^\varepsilon dx=\int_{\Omega} \chi_{\Omega_\varepsilon}fu^\varepsilon dx\leq C\|e(u^\varepsilon)\|_{L^2_{(\Omega_\varepsilon,\mathbb{R}_s^9)}}
\end{equation}
otherwise since $LD_0\hookrightarrow L^q(\Omega,\mathbb{R}^3)$ for all $q\in[1,\frac{3}{2}]$, in particular for $q_0=\frac{3}{2}$, we denote by $q'_0$ the conjugate of $q_0$, by H\"{o}lder  inequality, we obtain
\begin{equation*}
\int_{B_\varepsilon}fu^\varepsilon\leq \|f\|_{L^{q'_0}(B_\varepsilon,\mathbb{R}^3)}\|u^\varepsilon\|_{L^{q_0}(B_\varepsilon,\mathbb{R}^3)}
\end{equation*}
since $u^\varepsilon=0~\text{on}~\partial B_\varepsilon$, one has, according to Pioncar้'s type inequality see you (\cite{Temam}, p.121),
\begin{equation}\label{*}
\|f\|_{L^{q'_0}(B_\varepsilon,\mathbb{R}^3)}\|u^\varepsilon\|_{L^{q_0}(B_\varepsilon,\mathbb{R}^3)} \leq C{(\varepsilon\varphi_\varepsilon)}^{\frac{1}{q'_0}}\int_\Omega|e(u^\varepsilon)|\leq C{(\varepsilon\varphi_\varepsilon)}^{\frac{1}{q'_0}}(\int_{\Omega_\varepsilon}|e(u^\varepsilon)|+\int_{B_\varepsilon}|e(u^\varepsilon)|)
\end{equation}
such as $\varphi_\varepsilon$ is $Y$-periodic and for a small enough $\varepsilon$, than we have :
 \begin{equation*}
\varphi_\varepsilon<\frac{1}{\varepsilon{(1+C)}^{q'_0}},~~~~\text{ let }~~ c_\varepsilon=\frac{C}{\varepsilon(1+C)}.
\end{equation*}
According to $(4.4)$, and using $(4.5)$, $(4.6)$, then we obtain
\begin{equation*}
\|e(u^\varepsilon)\|^2_{L^2(\Omega_\varepsilon,\ree^9_s)}+\frac{1}{\varepsilon}\int_{B_\varepsilon}|e(u^\varepsilon)|\leq C+C\|e(u^\varepsilon)\|_{L^2(\Omega_\varepsilon,\ree^9_s)} +c_\varepsilon\int_{B_\varepsilon}|e(u^\varepsilon)|
\end{equation*}
Using Young inequality,
\begin{equation*}
\leq C+\frac{1}{2}\|e(u^\varepsilon)\|^2_{L^2(\Omega_\varepsilon,\ree^9_s)} +c_\varepsilon\int_{B_\varepsilon}|e(u^\varepsilon)|
\end{equation*}
so that
\begin{equation*}
\|e(u^\varepsilon)\|^2_{L^2(\Omega_\varepsilon,\ree^9_s)}+(\frac{1}{\varepsilon}-c_\varepsilon)\int_{B_\varepsilon}|e(u^\varepsilon)| \leq C
\end{equation*}
we obtain :
\begin{equation*}
\|e(u^\varepsilon)\|^2_{L^2(\Omega_\varepsilon,\ree^9_s)}+\frac{1}{\varepsilon}(1-\frac{C}{1+C})\int_{B_\varepsilon}|e(u^\varepsilon)| \leq C.
\end{equation*}
Therefore, we will have $(4.2)$ and $(4.3)$. According to (4.2), (4.3) and for a small
enough $\varepsilon$ the sequence $u^\varepsilon$ is bounded in $LD_0(\Omega)$.
\end{pf}

We give some lemmas that will be used in the sequel.
\begin{lem} Let $g\in C^\infty(\Sigma,\ree^9)$ and $u\in\mathcal{D}(\Sigma,\ree^3)$, so we have
\begin{equation*}
    \int_\Sigma \tau e(u)=-\int_\Sigma div_T(\tau)u
\end{equation*}
with $div_T(\tau)=div(\frac{\tau+\tau^T}{2}).$
\end{lem}
\begin{lem}
 Let $u$ be a regular function defined in a neighborhood of $\Sigma$, then
 \begin{equation*}
    \delta_j(\int_{0}^{\varepsilon\varphi_\varepsilon}u)=\varepsilon u(x',\varepsilon\varphi_\varepsilon)\delta_j\varphi_\varepsilon + \int_0^{\varepsilon\varphi_\varepsilon}\delta_ju.
 \end{equation*}
\end{lem}
This lemme is a consequence of (\cite{AcerbiBP} Proposition 2).\\

To apply the epi-convergence method, we need to characterize the
topological spaces containing any cluster point of the solution of
the problem $(4.1)$ with respect to the used topology, therefore the
weak topology to use is insured by the lemma 4.1. So the topological
spaces characterization is given in the following proposition.

Let us
\begin{equation*}
w^\varepsilon=\frac{1}{2\varepsilon\varphi_\varepsilon}\int_{-\varepsilon\varphi_\varepsilon}^{\varepsilon\varphi_\varepsilon} u^\varepsilon
\end{equation*}
\begin{prop}
The solution $u^\varepsilon $ of the problem (4.1) possess a cluster
point $u^*$ in $LD_0(\Omega)$, with respect to the weak topology and
 $u^*_{|_\Sigma}$ is a weak cluster point of $w^\varepsilon$ in $LD_0(\Sigma,\mathbb{R}^3).$
\end{prop}
\begin{pf}
According to a $(4.2)$, $(4.3)$ and for a small $\varepsilon$, the solution $u^\varepsilon$ is bounded in
$LD_0(\Omega)$, then It's relatively compact in $L^1(\Omega)$, this is consequence of (\cite{Temam}, Theorem1.4 p.117), and $e(u^\varepsilon)$ so for a subsequences of $u^\varepsilon$, still denoted by $u^\varepsilon$, there exists there
exists $u^*\in L^1(\Omega)$, such that
\begin{equation*}
u^\varepsilon\rightarrow u^*~\text{ in}~L^1(\Omega),
\end{equation*}
%and $$e(u^\varepsilon)\rightharpoonup e(u^*) \text{ in}~W^{1,1}_0(\Omega)$$
we have
\begin{equation*}
u^\varepsilon\rightharpoonup u^*~\text{ in}~LD_0(\Omega)
\end{equation*}
other hand
\begin{eqnarray*}
% \nonumber to remove numbering (before each equation)
\int_\Sigma|w^\varepsilon-u^\varepsilon_{|_\Sigma}|dx'\leq \int_\Sigma\frac{1}{2\varepsilon\varphi_\varepsilon}\int_{-\varepsilon\varphi_\varepsilon}^{\varepsilon\varphi_\varepsilon} |u^\varepsilon(x)-u^\varepsilon(x',0)|dx_3dx' \\
\leq \frac{C}{\varepsilon}\int_\Sigma\int_{-\varepsilon\varphi_\varepsilon}^{\varepsilon\varphi_\varepsilon} |\int^{x_3}_0\frac{\partial u^\varepsilon}{\partial x_3}(x',t)dt|dx_3dx' \\
\leq \frac{C}{\varepsilon}\int_\Sigma{(\varepsilon\varphi_\varepsilon)}^2 \int_{-\varepsilon\varphi_\varepsilon}^{\varepsilon\varphi_\varepsilon} |\frac{\partial u^\varepsilon}{\partial x_3}(x',x_3)|dx_3 dx' \\
\leq C\varepsilon\int_{B_\varepsilon}\nabla u^\varepsilon dx\leq C\varepsilon\int_{\Omega}e( u^\varepsilon)dx
\end{eqnarray*}
Thanks to Lemma 4.1 and the Young's inequality, so we have
$$\int_\Sigma|w^\varepsilon-u^\varepsilon_{|_\Sigma}|\leq C\varepsilon(\int_{\Omega_\varepsilon}e(u^\varepsilon)+\int_{B_\varepsilon}e(u^\varepsilon))$$
$$\leq C\varepsilon(C+C).$$
Then
\begin{equation*}
\lim_{\varepsilon\rightarrow 0}\int_\Sigma|w^\varepsilon-u^\varepsilon_{|_\Sigma}|=0
\end{equation*}
since $u^\varepsilon_{|_\Sigma}\rightharpoonup u^*_{|_\Sigma}$ in $LD_0(\Sigma)$, so $w^\varepsilon\rightharpoonup u^*_{|_\Sigma}$ in $LD_0(\Sigma).$
\end{pf}
\begin{rem}
The Proposition 4.2 remains true for any weak cluster
point  $u$ of a sequence $u^\varepsilon$ in $LD_0(\Omega,\ree^3)$
 satisfies (4.2) and (4.3).
\end{rem}
\vspace*{0.3cm}

To study the limit behavior of the solution of the problem (4.1), we will use the
epi-convergence method, (see Annex, definition ).
\section{Limit Behavior}
In this section, we are interested to the asymptotic behavior of the
solution of the problem (4.1) when  e  close to zero. In the sequel, we
consider the following functionals
\begin{equation}\label{}
    F_\varepsilon(v)=  \begin{cases}
 \frac{1}{2}\int_{\Omega_\varepsilon}a_{ijhk}e_{ij}(v)e_{hk}(v)dx
+ \frac{1}{\varepsilon}\int_{B_\varepsilon}|e(v)| &\mbox{if }v\in V^{\varepsilon}\\
 +\infty &\mbox{if } v \not\in V^{\varepsilon}
 \end{cases}
\end{equation}
\begin{equation*}
G(v)=-\int_\Omega fvdx, ~~ \forall v\in V^\varepsilon
\end{equation*}
 We design by $\tau_f$ the weak topology on the space. In the sequel, we shall
characterize, the epi-limit of the energy functional given by
$(5.1)$ in the following theorem :
\begin{thm}
Under $(2.1)$, $(2.2$), $(2.3$) and for $f\in
L^\infty(\Omega,\ree^3)$, there exists a functional
$F:W^{1,1}(\Omega)\rightarrow\ree\cup \{+\infty\}$ such that
\begin{equation*}
\tau_f-\lim_\varepsilon F^\varepsilon=F ~~\text{ in } W^{1,1}_0(\Omega)
\end{equation*}
where $F$ is given by
\begin{equation*} F(u)=  \begin{cases}
\frac{1}{2}\int_{\Omega} a_{ijhk}e_{ij}(u)e_{hk}(u)dx
+  m(\varphi)\int_{\Sigma}|e^*(u_{|_\Sigma})| &\mbox{if }u\in W^{1,1}_0(\Omega)\\
+\infty &\mbox{if } u\not\in W^{1,1}_0(\Omega)
\end{cases}.
\end{equation*}
\end{thm}
\begin{pf}
%%%%%%%%%%%%%%%%%%%%%%%%่่่่่่่่่่่่่่่่่77777777777777777777777777777777777777777
$\bullet-(a)$ We are now in position to determine the upper epi-limit.\\
Let $u\in LD_0(\Omega)$, as $C^\infty(\Omega)$ is dense in $LD_0(\Omega)$ see you (\cite{Temam}, p.116),  so there exists a sequence
$(u^n)$ in $C^\infty(\Omega)$ such that $(u^n)\rightharpoonup u$ weakly in $LD_0(\Omega)$.\\
Let us consider the sequence
\begin{equation*}
u^{n,\varepsilon}=\theta_\varepsilon(x)u^n_{|_\Sigma}+(1-\theta_\varepsilon(x))u^{n}
\end{equation*}
where $\theta$ is a regular function satisfies :
\begin{equation*}
\theta(x_3)=1\text{ if }|x_3|\leq1,~~\theta(x_3)=0\text{ if }|x_3|\geq2~~\text{and}~~|\theta'(x_3)|\leq2~\forall x\in\mathbb{R}
\end{equation*}
we set
\begin{equation*}
\theta_\varepsilon=\theta(\frac{x_3}{\varepsilon\varphi_\varepsilon})
\end{equation*}
we have
\begin{equation*}
F^\varepsilon(u^{\varepsilon,n})=\frac{1}{2}\int_{\Omega_\varepsilon}a_{ijhk}e_{ij}(u^{\varepsilon,n})e_{hk}(u^{\varepsilon,n})dx
+ \frac{1}{\varepsilon}\int_{B_\varepsilon}|e(u^{\varepsilon,n})|
\end{equation*}
which implies that

$$F^\varepsilon(u^{\varepsilon,n})=\frac{1}{2}\int_{|x_3|>2\varepsilon\varphi_\varepsilon}a_{ijhk}e_{ij}(u^{\varepsilon,n})e_{hk} (u^{\varepsilon,n})dx$$$$\hspace{4cm}+ \frac{1}{2}\int_{\varepsilon\varphi_\varepsilon<|x_3|<2\varepsilon\varphi_\varepsilon}a_{ijhk}e_{ij}(u^{\varepsilon,n})e_{hk} (u^{\varepsilon,n})dx $$$$+\frac{1}{\varepsilon}\int_{B_\varepsilon}|e(u^{\varepsilon,n})|$$
$$=\int_{|x_3|>2\varepsilon\varphi_\varepsilon}a_{ijhk}e_{ij}(u^{\varepsilon,n})e_{hk} (u^{\varepsilon,n})dx$$
$$\hspace{4cm}+ \frac{1}{2}\int_{\varepsilon\varphi_\varepsilon<|x_3|<2\varepsilon\varphi_\varepsilon}a_{ijhk}e_{ij}(u^{\varepsilon,n}) e_{hk}(u^{\varepsilon,n})dx $$ $$\hspace{2cm}+\frac{1}{\varepsilon}\int_{\Sigma}\varepsilon\varphi_\varepsilon|e^*(u^{\varepsilon,n}_{|_\Sigma})|.$$
As $\varphi_\varepsilon$ is bounded, then it's easy to prove that
\begin{equation*}
\lim_{\varepsilon\rightarrow0}\{~\frac{1}{2}\int_{\varepsilon\varphi_\varepsilon<|x_3|<2\varepsilon\varphi_\varepsilon}a_{ijhk}e_{ij} (u^{\varepsilon,n})e_{hk}(u^{\varepsilon,n})dx~\}=0.
\end{equation*}
Otherwise
$\varphi_\varepsilon\rightarrow m(\varphi)$ in $L^1(\Omega)$ see you Annex
so by passing to the upper limit, we obtain :
\begin{eqnarray*}
% \nonumber to remove numbering (before each equation)
 \limsup_{\varepsilon\rightarrow0}F^\varepsilon(u^{\varepsilon,n})= \limsup_{\varepsilon\rightarrow0}\{~ \frac{1}{2}\int_{|x_3|>2\varepsilon\varphi_\varepsilon}a_{ijhk}e_{ij}(u^{\varepsilon,n})e_{hk} (u^{\varepsilon,n})dx +\int_{\Sigma}\varphi_\varepsilon|e^*(u^{\varepsilon,n}_{|_\Sigma})|~\} \\
=\frac{1}{2}\int_{\Omega}a_{ijhk}e_{ij}(u^{n})e_{hk} (u^n)dx + m(\varphi)\int_{\Sigma}|e^*(u^n_{|_\Sigma})|.
\end{eqnarray*}

Since $u^n\rightarrow u$ in $C^\infty(\Omega)$, there fore according to the
classic result, diagonalization's Lemma, see (\cite{HA} p.32), there exists
a real function $n(\varepsilon): \ree^{+}\rightarrow\mathbb{N}$
increasing to $+\infty$, such that
$u^{\varepsilon,n(\varepsilon)}\rightharpoonup u$ in
$C^\infty(\Omega)$  when $\varepsilon\rightarrow 0.$\newline
Consequently, we have
\begin{eqnarray*}
% \nonumber to remove numbering (before each equation)
\limsup_{\varepsilon\rightarrow0}F^\varepsilon(u^{\varepsilon,n(\varepsilon)})\leq \limsup_{n\rightarrow0}\limsup_{\varepsilon\rightarrow0}F^\varepsilon(u^{\varepsilon,n}) \\
\leq \frac{1}{2}\int_{\Omega} a_{ijhk}e_{ij}(u)e_{hk}(u)dx+ m(\varphi)\int_{\Sigma}|e^*(u_{|_\Sigma})|
\end{eqnarray*}
\\
%รงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรง PROOF OF (B) %9999999999999รงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรงรง
$\bullet-(b)$ We are now in position to determine the lower epi-limit.\\
Let as $(u^\varepsilon)\subset V^\varepsilon$ such as $u^\varepsilon\rightharpoonup u$ in $LD_0(\Omega),$
If $\liminf_{\varepsilon\rightarrow0}F^\varepsilon(u^\varepsilon)=+\infty$ there is nothing
to prove, because
\begin{eqnarray*}
\frac{1}{2}\int_{\Omega} a_{ijhk}e_{ij}(u)e_{hk}(u)dx+ m(\varphi)\int_{\Sigma}|e^*(u_{|_\Sigma})|\leq+\infty.
\end{eqnarray*}
Otherwise, we suppose $\liminf_{\varepsilon\rightarrow0}F^\varepsilon(u^\varepsilon)<+\infty,$ there exists a subsequence of $F^\varepsilon(u^\varepsilon)$,
still denoted by $F^\varepsilon(u^\varepsilon)$ and a constant $C >0$, such that \\
$F^\varepsilon(u^\varepsilon)\leq C$, which implies
that
\begin{eqnarray*}
% \nonumber to remove numbering (before each equation)
\|e(u^\varepsilon)\|^2_{L^2(\Omega_\varepsilon,\ree^9_s)}\leq C \\
\frac{1}{\varepsilon}\int_{B_\varepsilon}|e(u^\varepsilon)|\leq C.
\end{eqnarray*}

Then $\chi_{\Omega_\varepsilon}e(u^\varepsilon)$ is bounded in $L^2(\Omega)$, so for a subsequence of $\chi_{\Omega_\varepsilon}e(u^\varepsilon)$, still denoted by $\chi_{\Omega_\varepsilon}e(u^\varepsilon)$
we then show easily, like in the proof of the above proposition, that
\begin{eqnarray*}
\chi_{\Omega_\varepsilon}e(u^\varepsilon)\rightharpoonup e(u)~ \text{in}~L^2(\Omega)
\end{eqnarray*}
From the subdifferentiability's inequality of $u\rightarrow\frac{1}{2}\int_{\Omega_\varepsilon} a_{ijhk}e_{ij}(u)e_{hk}(u)dx$
and passing to the lower limit, we obtain
\begin{equation}\label{}
    \liminf_{\varepsilon\rightarrow0}\frac{1}{2}\int_{\Omega_\varepsilon} a_{ijhk}e_{ij}(u^\varepsilon)e_{hk}(u^\varepsilon)dx\geq \frac{1}{2}\int_{\Omega} a_{ijhk}e_{ij}(u)e_{hk}(u)dx.
\end{equation}


Let us set, for $\eta<\frac{\varepsilon}{2}$
\begin{eqnarray*}
B_\eta=\{x\in \Omega : |x_3|<\eta\}.
\end{eqnarray*}
According to the diagonalization's lemma (\cite{HA}, Lemma1.15 p.32), there exists a function $\eta(\varepsilon):\mathbb{R}^+\rightarrow\mathbb{R}^+$ decreasing to 0 when $\varepsilon\rightarrow0$ such that
\begin{equation}\label{}
    \liminf_{\varepsilon\rightarrow0}\int_{B^{\eta(\varepsilon)}}|e(u^\varepsilon)|\geq \liminf_{\eta\rightarrow0}\liminf_{\varepsilon\rightarrow0}\int_{B_\eta}|e(u^\varepsilon)|
\end{equation}
since
\begin{eqnarray*}
\int_{B^{\eta}}|e(u^\varepsilon)|\geq\int_{B_\eta}\phi(e(u^\varepsilon)-e(u))+\int_{B^{\eta}}\phi(e(u))~~\forall \phi\in C^\infty_0(B_\eta,\mathbb{R}^9_s)
\end{eqnarray*}
it follow that
$$\liminf_{\varepsilon\rightarrow0}\int_{B^{\eta}}|e(u^\varepsilon)|\geq \int_{B^{\eta}}\phi(e(u))~~\forall \phi\in C^\infty_0(B_\eta,\mathbb{R}^9_s)$$
therefore,
$$\liminf_{\varepsilon\rightarrow0}\int_{B^{\eta}}|e(u^\varepsilon)|\geq \int_{B^{\eta}}e(u),$$

According to a Lemma 4.3, and let $w^\varepsilon$ be the sequence define before the Proposition 4.3, we have
\begin{equation}
   \liminf_{\varepsilon\rightarrow0}\int_{B^{\eta}}|e(u^\varepsilon)|\geq\int_{\Sigma}e^*(w^\varepsilon)-\int_{B_\eta} \varepsilon\varphi_\varepsilon\delta\varphi_\varepsilon\otimes_sU^\varepsilon
\end{equation}
Or
\begin{equation*}
   U^\varepsilon=[u^\varepsilon(x',\varepsilon\varphi_\varepsilon)+ u^\varepsilon(x',-\varepsilon\varphi_\varepsilon)]
\end{equation*}
thanks to a Lemma 4.2, let $g\in \mathcal{D}(\Sigma,\ree^9)$ we have
\begin{equation*}
    \int_{\Sigma}g e^*(w^\varepsilon)=-\int_{\Sigma}div_Tg(\frac{1}{\varepsilon\varphi_\varepsilon}\int^{ \varepsilon\varphi_\varepsilon}_{\varepsilon\varphi_\varepsilon}u^\varepsilon)
\end{equation*}
thanks to a Proposition 4.2 and $\varphi_\varepsilon\rightarrow m(\varphi)$ in $L^1(\Sigma)$, so passing to limit, we obtain
\begin{equation}
 \int_{\Sigma}g e^*(w^\varepsilon)=-m(\varphi)\int_{\Sigma}div_Tgu_{|_\Sigma}
 = m(\varphi)\int_{\Sigma}ge^*(u_{|_\Sigma})~~\forall g\in \mathcal{D}(\Sigma,\ree^9)
\end{equation}

By passing to the limit, $(\eta\rightarrow0)$, in (5.4) we have
\begin{equation*}
    \liminf_{\eta\rightarrow0} \liminf_{\varepsilon\rightarrow0}\int_{B^{\eta}}|e(u^\varepsilon)|\geq m(\varphi)\int_{\Sigma}e^*(u_{|_\Sigma})
\end{equation*}

According to  the definition of $B_\eta$, (5.3), we deduce that
\begin{equation}%\label{}
    \liminf_{\varepsilon\rightarrow0}\int_{B^{\varepsilon}}|e(u^\varepsilon)|\geq m(\varphi)\int_{\Sigma}e^*(u_{|_\Sigma})
\end{equation}
Hence (5.2) and (5.6),
\begin{equation*}
    \liminf_{\varepsilon\rightarrow0}F^\varepsilon(u^\varepsilon)\geq \frac{1}{2}\int_{\Omega} a_{ijhk}e_{ij}(u)e_{hk}(u)dx +m(\varphi)\int_{\Sigma}e^*(u_{|_\Sigma})
\end{equation*}

For $u\in LD_0(\Omega)$ and $u^\varepsilon\in V^\varepsilon$,
such that $u^\varepsilon\rightharpoonup u$ in $LD_0(\Omega)$,
Assume that
$$\liminf_{\varepsilon\rightarrow 0}F^\varepsilon(u^\varepsilon)<+\infty.$$
So there exists a constant $C > 0$ and a subsequence of
$F^\varepsilon (u^\varepsilon)$, still de noted by $F^\varepsilon
(u^\varepsilon)$, such that $$F^\varepsilon(u^\varepsilon)<C.$$ So
$u^\varepsilon$ verifies the following evaluation (4.2) and (4.3),
as $u^\varepsilon\rightharpoonup u$ in $LD_0(\Omega)$ thanks to
the Remark 4.1 we have $u\in \mathbb{H}_0^1(\Omega)$, what contradicts the
fact that $u\in LD_0(\Omega)\setminus \mathbb{H}_0^1,$
consequently we have $$\liminf_{\varepsilon\rightarrow
0}F^\varepsilon(u^\varepsilon)=+\infty$$

%$$\frac{1}{\varepsilon}\int_{B^\varepsilon}|e(w^\varepsilon)|\leq C,$$and
%$$w^\varepsilon\rightharpoonup u_{|_\Sigma} \text{ in } LD_0(\Omega)$$we obtain
%$$\frac{1}{\varepsilon}\int_{B^\varepsilon}|e(w^\varepsilon)|=\frac{1}{\varepsilon}\int_{\Sigma} %\int_{-\varepsilon\varphi_\varepsilon}^{\varepsilon\varphi_\varepsilon} |e(w^\varepsilon(x',x_3)|= %\frac{1}{\varepsilon}\int_{\Sigma}\varepsilon\varphi_\varepsilon|e^*(w^\varepsilon)|$$
%using subdifferentiability's inequality, and $\varphi_\varepsilon\rightharpoonup^*m(\varphi)\text{ in }L^\infty$, we obtain
%\begin{equation}\label{}
 %  \frac{1}{\varepsilon}\int_{B^\varepsilon}|e(w^\varepsilon)|\geq m(\varphi)\int_{\Sigma}|e^*(u_{|_\Sigma})|
%\end{equation}

%we combined (5.2), (5.3) and (5.4) we have obtain

%$$\liminf_{\varepsilon\rightarrow0}F^\varepsilon(u^\varepsilon)\geq \frac{1}{2}\int_{\Omega} a_{ijhk}e_{ij}(u)e_{hk}(u)dx+ %m(\varphi)\int_{\Sigma}|e^*(u_{|_\Sigma})|$$
Hence the proof of the Theorem 5.1 is complete.
\end{pf}
In the sequel, we determine the limit problem linked to $(4.1)$,
when $\varepsilon$ approaches to zero. Thanks to the epi-convergence
results, see Annex Theorem 7.1, Proposition 7.1 and the
theorem 5.1, according to the $\tau_f$-continuity of the functional
$G$ in $W^{1,1}_0(\Omega)$, we have $F^\varepsilon+G$
$\tau_f$-epiconverges to $F+G$ in $LD_0(\Omega)$
\begin{prop}
For any $f\in L^1(\Omega,\ree^3)$, there exists $u^{*}\in
LD_0(\Omega,\ree^3)$ satisfies $$u^\varepsilon\rightharpoonup
u^{*}~~\text{in}~LD_0(\Omega,\ree^3),$$
$$F(u^{*})+G(u^{*})=\inf_{u\in LD_0(\Omega)}\{F(u)+G(u)\}.$$
\end{prop}
\begin{pf}
Thanks to Lemma 4.1, the family ${(u^\varepsilon)}_\varepsilon$ is
bounded in $L^1(\Omega),$ therefore it passes a $\tau_f$-cluster
point $u^{*}$ in $L^1(\Omega).$ And thanks to a classical
epi-convergence method, theorem 7.1, it follows that $u^{*}$ is a
solution of the problem : Find
\begin{equation}\label{}
\inf_{u\in LD_0(\Omega)}\{F(u)+G(u)\}
\end{equation}
Since $F=+\infty$ on $LD_0(\Omega)\setminus \mathbb{H}_0^1(\Omega)$,
so $(5.6)$ became $$\inf_{u\in \mathbb{H}_0^1(\Omega)}\{F(u)+G(u)\}.$$

According to the uniqueness of solutions of problem $(5.7)$, so
$u^\varepsilon$ admits an unique $\tau_f$-cluster point $u^{*}$, and
therefore $u^\varepsilon\rightharpoonup u^{*}$ in $
LD_0(\Omega)$
\end{pf}
\section{Conclusion}
Using the epi-convergence method, we showed that the question of
finding the limit problem, composed of a classical linear elasticity problem posed
over $\Sigma$, contains an interface condition which depends on the displacement field
jump. We found the same result of A. Ait Moussa and J. Messaho, with p=1 in \cite{AitJ}.

\section{Annex}

\begin{Defn}(\cite{HA} Definition 1.9). %to create the definition
Let $(\mathbb{X},\tau)$ be a metric space, ${(F^\varepsilon)}_\varepsilon$ and $F$
be functionals defined on $\mathbb{X}$ and with value in $\mathbb{R}\cup\{+\infty\}$.
$F^\varepsilon$ epi-converges to $F$ in $(\mathbb{X},\tau)$, noted $\tau-\lim_e F^\varepsilon=F$, if the following assertions
 are satisfied :\\
$~~~~~~~~\bullet~\forall x$ in $\mathbb{X}$, there exists $x_\varepsilon^0,$ $x_\varepsilon^0\rightarrow^\tau x$, such that $\limsup_{\varepsilon\rightarrow0}F^\varepsilon(x_\varepsilon^0)\leq F(x)$.\\
$~~~~~~~~\bullet~\forall x,x_\varepsilon$ with $x_\varepsilon\rightarrow^\tau x$, $\liminf_{\varepsilon\rightarrow0}F^\varepsilon(x_\varepsilon^0)\geq F(x)$.\\
 We have the following stability result for epi-convergence.
\end{Defn}

\begin{prop}{(\cite{HA} p.40)}\\
Suppose that $F^\varepsilon$ epi-converge to $F$, in $(\mathbb{X},\tau)$ and that $G:\mathbb{X}\rightarrow\mathbb{R}\cup\{+\infty\}$, is $\tau$-continuous. Then $(F^\varepsilon+G)$ epi-converges to $F+G$ in $(\mathbb{X},\tau)$.
\end{prop}

This epi-convergence is a special case of the $\Gamma$-convergence introduced by De
Giorgi (1979), for more detail \cite{HA}. It is well suited to the asymptotic analysis of sequences of
minimization problems since one has the following fundamental result.
\begin{thm}{(\cite{HA} p.27)}\\
Suppose that : \\
$~~~~~~(1)$ $F^\varepsilon$ admits a minimizer on $\mathbb{X}$.\\
$~~~~~~(2)$ The sequence $u^\varepsilon$ is $\tau$-relatively compact.\\
$~~~~~~(3)$ The sequence $F^\varepsilon$ epi-converges to $F$ in this topology $\tau$.\\
Then every cluster point $u$ of the sequence $u^\varepsilon$ minimizes $F$ on $\mathbb{X}$ and
$$\lim_{\varepsilon'\rightarrow0} F^{\varepsilon'}=F(u),$$
where ${(u^{\varepsilon'})_{\varepsilon'}}$ denotes any subsequence of ${(u^{\varepsilon})}_\varepsilon$ which converges to $u$.
\end{thm}

\begin{lem}\label{lemma1} %to create environment to lemma
Let $\varphi\in L^\infty(\Sigma)$, a $Y$-periodic, $Y=]0,1[\times]0,1[.$ Let
\begin{equation*}
    \varphi_\varepsilon(x)=\varphi(\frac{x}{\varepsilon}), \text{for a small enough } \varepsilon>0.
\end{equation*}
So that
\begin{equation*}
    \varphi_\varepsilon\rightarrow m(\varphi) \text{ in } L^s(\Sigma) \text{ for } 1\leq s\leq\infty,\\
     \varphi_\varepsilon\rightharpoonup^* m(\varphi) \text{ in } L^\infty(\Sigma).
\end{equation*}
\end{lem}
\begin{pf}
Since $\varphi_\varepsilon$ is a $\varepsilon Y$-periodic, so one has
\begin{equation*}
    \varphi_\varepsilon\rightharpoonup m(\varphi) \text{ in } L^s(\Sigma) \text{ for } 1\leq s\leq\infty,\\
     \varphi_\varepsilon\rightharpoonup^* m(\varphi) \text{ in } L^\infty(\Sigma).
\end{equation*}
Since $\varphi$ is bounded in $\Sigma$, so for evry $s\geq1$, there existes a constant $C>0$, such that
\begin{equation*}
    \int_\Sigma{|\varphi_\varepsilon-m(\varphi)|}^s\leq C\int_\Sigma{|\varphi_\varepsilon-m(\varphi)|}
\end{equation*}
\begin{equation}
    \leq C[\int_{\varphi\geq m(\varphi)}{(\varphi_\varepsilon-m(\varphi))}-\int_{\varphi\leq m(\varphi)}{(m(\varphi)-\varphi_\varepsilon)}].
\end{equation}
Passing to the limit in (7.1), one has $\varphi_\varepsilon\rightarrow m(\varphi)$ in $L^s(\Sigma)$ for $1\leq s\leq\infty.$

\end{pf}
%\begin{cor}\label{corollary1} %to create the corollary
%This is the environment to corollary
%\end{cor}

%\begin{Rem} %to create the remark
%This is the environment to remarks.
%\end{Rem}


%%% to create the Acknowledgments


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\end{document}
